a)
X -package is delivered
Y - weight is 2 lbs or more
P(X) = 0.20
P(Y|X) = 0.12
P( Y' |X') = 0.08
P( X|Y) = P(X and Y) /P(Y)
P(X and Y) = P(Y|X) P(X) = 0.12* 0.20 = 0.024
P(Y) = P(Y|X) P(X) + P(Y|X') P(X')
= 0.12*0.20 + 0.8 * 0.92
= 0.76
hence
required probability = 0.024/0.76
= 0.0315789
b)
P(X'|Y) = P(X'and Y) /P(Y)
= 1- 0.0315789
= 0.968421
Suppose that out of 20% of all packages from Amazon are delivered by UPS, 12% of...
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