Question

The pole is subjected to the force (F) which has components Fx = 1.2 kN and Fz = 1.05 kN. If β = 79 ∘

1. Determine the magnitude of Fy. (Figure 1)

Express your answer with the appropriate units.

2 Determine the magnitude of F.

Express your answer with the appropriate units.

Answer 1

Fx = 1.2 kN

Fz = 1.05 kN.

β = 79

1.

tan β = F_z / F_y

F_y   =  F _z /  tan β

tan79° = 5.15

F_y = 1.05 / 5.15

F_y = 0.20 kN

2.

F = $\sqrt{}$Fx ² + Fy² +  Fz ²

F = $\sqrt{}$1.2 ²  + 1.05 ²  + 0.20 ²

= $\sqrt{}$  2.5825

=  1.607 kN