Question

Please answer problem 2 based of information from problem 1 theres is two photos. I have the answer to problem 1.

e = 1.6 x 10-19 For these problems, use the right-handed coordinate system shown above. 1) At the location of a proton there is a magnetic field of magnitude 0.36 T in the -X direction. a) If the proton is not moving, what are the magnitude and direction of the magnetic force on the proton? b) If the proton is moving at 6.0 x 10 m/s in the +x direction, what are the magnitude and direction of the magnetic force on the proton? c) If the proton is moving at 6.0 x 10 m/s in the +y direction, what are the magnitude and direction of the magnetic force on the proton?

Answer 1

Now if we replace posoton by an electron men change q will be negative. le q=-6 Now @ (o=o, men [E=0 © B = 0,36 T (-) e = 6.0 x16 5 m/ (+²). he x B =- â xã = 0 since therefore IF =0 0 % = 6.0 X10 5 m/s ty 5 ^ 04 then F = -1.6x10 c x -14 - 3.456 X10 N IF I = 3.456 X10-14 N dish = (-zdigh)