// Replace line 16 withe below code
for(i = 0;i<dataPoints.length; i++){
if(dataPoints[i]<minValue){
dataPoints[i] = dataPoints[i]*2;
}
}
// Replace line 16 withe below code
for(i = 0;i<dataPoints.length; i++){
if(dataPoints[i]<controlValue){
dataPoints[i] = dataPoints[i]*2;
}
}
Double any element's value that is less than minValue. Ex: If minValue 10, then dataPoints =...
Double any element's value that is less than minVal. Ex: If minVal = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. #include <stdio.h> int main(void) { const int NUM_POINTS = 4; int dataPoints[NUM_POINTS]; int minVal; int i; dataPoints[0] = 2; dataPoints[1] = 12; dataPoints[2] = 9; dataPoints[3] = 20; minVal = 10; /* Your solution goes here */ for (i = 0; i < NUM_POINTS; ++i) { printf("%d ", dataPoints[i]); } printf("\n"); return 0; }
In the C language Double any element's value that is less than controlVal. Ex: If controlVal = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. #include <stdio.h> int main(void) { const int NUM_POINTS = 4; int dataPoints[NUM_POINTS]; int controlVal; int i; scanf("%d", &controlVal); for (i = 0; i < NUM_POINTS; ++i) { scanf("%d ", &(dataPoints[i])); } /* Your solution goes here */ for (i = 0; i < NUM_POINTS; ++i) { printf("%d ", dataPoints[i]); }...
in C++ Problem: Subtract 4 to any element's value that is greater than maxVal. Ex: If maxVal = 10, then dataPoints = {2, 12, 9, 20} becomes {2, 8, 9, 16}. ------------------------ #include #include using namespace std; int main() { int maxVal; int NUM_POINTS; unsigned int i; cin >> maxVal; cin >> NUM_POINTS; vector dataPoints(NUM_POINTS); for (i = 0; i < dataPoints.size(); ++i) { cin >> dataPoints.at(i); } /* Your solution goes here */ for (i = 0; i <...
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the element. Ex: lowerScores = {5, 0, 2, -3} becomes {4, 0, 1, 0}. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int SCORES_SIZE = 4; int[] lowerScores = new int[SCORES_SIZE]; int i; for (i = 0; i < lowerScores.length; ++i) { lowerScores[i] = scnr.nextInt(); }...
1. Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2 , then numMatches should be 3. Your code will be tested with the following values: matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above) matchValue: 0, userValues: {0, 0, 0, 0} matchValue: 10, userValues: {20, 50, 70, 100} What i am given: import java.util.Scanner; public class FindMatchValue...
Answer in JAVA 1. Complete the method definition to output the hours given minutes. Output for sample program: 3.5 import java.util.Scanner; public class HourToMinConv { public static void outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ } public static void main (String [] args) { Scanner scnr = new Scanner(System.in); double minutes; minutes = scnr.nextDouble(); outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0, and 0.0. System.out.println(""); } } 2....
Complete the do-while loop to output 0 to countLimit. Assume the user will only input a positive number. import java.util.Scanner; public class CountToLimit { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); int countLimit = 0; int printVal = 0; // Get user input countLimit = scnr.nextInt(); printVal = 0; do { System.out.print(printVal + " "); printVal = printVal + 1; } while ( /* Your solution goes here */ ); System.out.println(""); return; } }
1. Array testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8. What i am given: import java.util.Scanner; public class SumOfExcess { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int NUM_VALS =...
Getting error: Exited with return code 1. Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 4 out of bounds for length 4 at main.main(main.java:435) Problem: Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. My code: import java.util.Scanner; public class CourseGradePrinter { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int NUM_VALS = 4; int []...
Write a for loop to print all NUM_VALS elements of array hourlyTemp. Separate elements with a comma and space. Ex: If hourlyTemp = {90, 92, 94, 95}, print: 90, 92, 94, 95 Your code's output should end with the last element, without a subsequent comma, space, or newline. import java.util.Scanner; public class PrintWithComma { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int NUM_VALS = 4; int[] hourlyTemp = new...