Question

Double any element's value that is less than minVal. Ex: If minVal = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}.

#include <stdio.h>

int main(void) {

const int NUM_POINTS = 4;

int dataPoints[NUM_POINTS];

int minVal;

int i;

dataPoints[0] = 2;

dataPoints[1] = 12;

dataPoints[2] = 9;

dataPoints[3] = 20;

minVal = 10;

/* Your solution goes here */

for (i = 0; i < NUM_POINTS; ++i) {

printf("%d ", dataPoints[i]);

}

printf("\n");

return 0;

}

Answer 1

C Program:

#include <stdio.h>

int main(void) {

const int NUM_POINTS = 4;

int dataPoints[NUM_POINTS];

int minVal;

int i;

dataPoints[0] = 2;

dataPoints[1] = 12;

dataPoints[2] = 9;

dataPoints[3] = 20;

minVal = 10;

for(i=0; i<NUM_POINTS; i++)

{

if(dataPoints[i] < minVal)

dataPoints[i] = 2*dataPoints[i];

}

for (i = 0; i < NUM_POINTS; ++i) {

printf("%d ", dataPoints[i]);

}

printf("\n");

return 0;

}