Question

1 out of 3 attempts Steam is leaving a pressure cooker whose operating pressure is 30 psia. It is observed that the A amount of liquid in the cooker has decreased by 0.43 gal in 20 minutes after the steady operating conditions are established, and the cross-sectional area of the exit opening is 0.15 h . Determine (a) the mass flow rate of the steam and the exit velocity × 10(select)- Ibm/s ft/s (b) the total and flow energies of the steam per unit mass, e flow Btu/lbm Btu/lbm and (e) the rate at which energy is leaving the cooker by steam. Btu/s mass

Answer 1

Given that A pressure cooker operating pressure is 30 psia. It is observed that the amount of liquid in the cooker has decreased by 0.43 gal in 20 minutes the exit opening is 0.15 h and also take the properties of liquid water at P = 30 psia v_f = 0.017 ft^3/lbm h_f = 1.0178 Btu/lbm v_g = 13.799 ft^3/lbm h_g = 1164.1 Btu/lbm (a) Given that the volume of cooker v = 0.43 gal Now we have to calculate the flow of mass rate m degree m = m/t = v/v_f/t 0.93 times 0.017/20 times 60 times 0.13368 Since 1 gal = 0.13368 ft^3 t = 20 minutes t = 20 minutes \r\n Now m = 0.00781/1200 times 0.13368 = 6091 times 0.13368 times 10^-6 = 8.1 433 times 10^-7 therefore m = 8.1433 times 10^-7 Calculate the exit velocity is m = rho_AV m = AV/v_g V = m times v_g/A