Question

For 440 nm wavelength light and a slit separation of 0.14 mm, what are the angular positions (in degrees) of the seventh and ninth maxima in the double slit interference pattern? (Consider the central maximum to be the zeroth maximum.) seventh maximum ninth maximum 0 O

Answer 1

For 440 non wavelength light and a slit seperation of 0.14 min, what are the angular positions (in degrees) of the seventh and ninth maxima in the double slit interference patterna a consider the central maximum to be the zeroth maximum) seventh maximum 0 ninth maximum Given: wavelength of the light = 4400m - 440x10. Slit seperation d -0.14 mm = 0.14*177 m 03 The condition for masima is dsino = m.n. where m = order of dithoution Thus for seventh maxima m=7 dsino = 7.7 sino = 7.A 7x440x109 0.14 x 102 sino 308086 0.14x100 22,000x lot 10 9+1 22,000x106 .. sino = 0.22 0 = sini (0.22) = 12.70° .. 0= 12.700 I seventh maximum. For ninth maximum mag d sinoma sino= mit 9x4408109 0.14x100 d sino 39608 106 28285 x 10 6 = 0.282 0.14 sin (0.282) = 16.37° o = 16.370 T for ninth onaxionym.