Question

A voltmeter and an ammeter are used to respectively monitor the voltage across and the current through a resistor connected to an AC source. If the resistor has a value of 14.0 Ω and the ammeter reads 8.04 A, determine the following.

(a)

the rms voltage (in V) across the resistor

V

(b)

the peak voltage (in V) of the source

V

(c)

the maximum current (in A) in the resistor

A

(d)

the average power (in W) delivered to the resistor

W

Answer 1

Here nooltmeter mesures measures Current. 2. Ipms ( a ) mesures voltage and voltage and ammeter. Ammeter measures the roms current. =:8.04A; Resistance (R)= 14.012; now, soms voltage across the resistor is, 8.0 44.14 Volt EllR. 56 Volt voltage across the resistor [112.56 [V Vams = Irms x R á poms (b now, peak voltage (Vo) = Vomax R =1159.1811V 2. peak voltage of the source is [159.18][v ☺) manimum eurrenz (To) - Irms *13 28.04xVB. A = 11.37 A : maximum current in resistor in [1] • 37 TA average power (P) = fpms x Irms = 11.3-5.6 8.04 W average power delivered to = 1904.98 W the resistor is 1904.98 [ IN