Question

In this problem,

* prompt the user to enter the rate at which x is moving.

* Create a vector of time values from 0 to 15.

* Use the following equations to calculate the height over time and the volume over time.

x = xRate * time

yRate = 2x * xRate

y = yRate * time

* Display your results in a table format where time is the first column, x is the second column, y is the third column, and the rate of y is the fourth column, Add a header

line to your table.

Answer 1

SOLUTION-

Below is the code :)

Code-

clc%clears screen
clear all%clears history
close all%closes all files

xRate=input('Enter the rate of x moving ');
time=[0:15];
x=xRate.*time;
yRate=2*x*xRate;
y=yRate.*time;
data=[time',x',y',yRate'];

VarName={'Time','x','y','Rate_Of_y'};
T=table(data(:,1),data(:,2),data(:,3),data(:,4),'VariableNames',VarName);
disp(T)

OUTPUT-

Enter the rate of x moving 2 Time Rate_of_Y X Y 0 1 2 0 8 16 2 3 G 32 40 5 6 7 E 56 10 12 14 16 18 20 22 0 8 32 72 125 200 296 392 512 648 800 968 1152 1352 1565 1800 72 80 94 10 11 12 13 14 15 26 28 30 104 112 120

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