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Question 10 (1 point) In Drosophila, the mutant black (b) has a black body and the wild-type (b+) has a gray body; the mutant vestigial (v) has wings that are short and crumpled compared the long wild-type wings (V+). These genes are linked and are located on the X- chromosome. A cross between a female fly and a black, vestigial winged male fly produced the following progeny: gray (b+), normal (v+) 20 gray (b+), vestigial (v) 120 black (b), normal (v+) 123 black (b) vestigial (v) 25 What is the map distance between the two genes? A) 13.3 CM B) 72.3 CM C) 84.4 CM D) 15.6 CM O 31 g e Ae

Answer 1

= 123 Government of West Bengal Grey (6) Norman() = 20 Grey (6+) Vestigiar o (W) (20 Black (6) Norman ( vt) Black CH(6) Vestigiar a la 25 I emale is wild type (6) y may and Norman (V+). recombination frequency a Number of recombe nant pregeny floo Toton no. here, Grey-ventiliar Black normal se combinant type of recombinant - 120 + 123 = 243 Total = 243T 20+ 25 = 288, Recombination of sequency so, the distance 84.4 243 288 x 100 between two grenres 84.37 2 white eyed female will be abowo Normas reyed f male x xw 1 x\sy yo XW thy yw XI will be xWyw sed eyed because this secesive, fene
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be xwy will male School Education Department white eyed. с parental type ! in 2 at or ct at 6 ct erre combinat 1 2 6T с --- R2. Com Comparing Pi with bc RI comparing P2 with st at 6 in each genc is altered only possible if the in present in middle gene the of krene. so grene order is e

School Education Department Sickle cen is autosomal secesine so two anelen would have to be mutate d to results in disease. wild type = A. rautated u za a a Aa Aa Aa a is Carier is discared. so the so- the option B is Conecta
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