Homework Answers
Answer: -200 kJ/kg
For process 1-2, heat transferred is Q1 = area enclosed by the trapezium from 1 to 2 with x-axis
= 0.5(100+400)*(5-1) = 1000 kJ/kg
For process 2-3, heat transferred is Q2 = area enclosed by the rectangle from 2 to 3 with x-axis
= 400*(5-3) = 1200 kJ/kg
So, net heat transfer in process 1-2-3 = Q1 - Q2 = 1000-1200 = -200 kJ/kg.
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the heat transfer
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