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The heat transfer to the system, in kJ/kg, for the reversible process 1-2-3 shown in the figure is closer T(K) 400 100 2 5 s
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Answer #1

(dq=JT ds 1.t area of Tds graphy dq = (100+400) y 3x400 da = 1000- 1200 -200 11] 4. = -200 kg ks

ANSWER = - 200kj/kg

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