Question

The following data was obtained on the rate of hydrolysis of 14% sucrose in 0.099 mol L aqueous HCl solution at 35 °C. Time (min) 9.32 59.60 93.18 142.9 294.8 589.4 Sucrose remaining (%) 96.5 80.3 71.0 59.1 32.8 11.1 a) What is the order of the reaction with respect to sucrose? b) What is the value of the rate constant, k?

Answer 1

GHIRO "ام 2.303 log Co + Cette of G2 H₂2 1 & 2 Concess) a) We have the formule, for let order reaction if the value of k is constant in each case. = 0.247 +0.012= 3.0x103 min iig x= 2.303 = 0.0386*0.093 = 3.5*163 mint 59.60 111> K- = 0.0247 *0.148 = 3.6X163 min 2.303 9.32 log 16.5 log 80.3 2.303 93.18 2.303 142.9 log = 0.016140.227 = 3.68 103 min 59. v k = 2.303 294.8 log loo 32.8 = 0.0078 x 0.484 = 3.7 x 10 min = 0.0039 x 0.954 = 3-7x1ő mia vis = 2.303 log 589.4 the value of k is found to be constart, the hydrolysing of sucrose is Pseudo first Order reaction. by Here -3 K [H₂o = 3.6 x 10 per min. and [H₂OJ = 0.ogg mot torm is given. 3.64 103 min 0.099 M = 3.637x 102 m Mint