in a similar experiment, if we want to buoy a 0.147-kg solid platinum object in water...
in a similar experiment, if we want to buoy a 0.147-kg solid platinum object in water with an attached string from above, what is the tension in Newtons required to support the piece of platinum?
Homework Answers
mass of he solid platinum object m_platinum=0.147 kg
density of platinum, rho_platinum=21450 kg/m^3
volume of the given platimum v=m/(rho_platinum)
now,
buoyancy force FB=m_water*g
FB=(rho_water*V_water)*g
FB=(rho_water*(m_platimum)/(rho_platimum)*g)
FB=(1000*(0.147/(21450))*9.8)
FB=6.72*10^-2 N
and
tension T=(m_platinum*g)-FB
T=(0.147)*9.8-(6.72*10^-2)
T=1.373 N
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