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Miss rate is 3%. An 4. For a given application, 30% of the instructions require memory...
AMAT = Time for a hit + (Miss rate x Miss penalty) For a data cache with a 4% miss rate and a 5-cycle hit latency, calculate the average memory access time (AMAT). Assume that latency to memory and the cache miss penalty together is 100 cycles. Note: The cache must be accessed after memory returns the data.
4B, 20%) compare performance of a Processor with cache vs. without cache. Assume an Ideal processor with 1 cycle memory access, CPI1 Assume main memory access time of 8 cycles Assume 40% instructions require memory data access Assume cache access time of I cycle Assume hit rate 0.90 for instructiens, 0.80 for data Assume miss penalty (time to read memory inte cache and from cache to Processor with cache processor) is 10 cycles >Compare execution times of 100-thousand instructions: 4B,...
Suppose you have a machine with separate I- and D- caches. The miss rate on the I-cache is 2.6% , and on the D-cache 3.8%. On an I-cache hit, the value can be read in the same cycle the data is requesfed. On a D-cache hit, one additional cycle is required to read the value. The miss penalty is 100 cycles for data cache, 150 for I-cache. 40% of the instructions on this RISC machine are LW or SW instructions,...
Question 4 - [25 Points] Part (a) - Average Access Time (AMAT) The average memory access time for a microprocessor with One (1) level (L1) of cache is 2.4 clock cycles - If data is present and valid in the cache, it can be found in 1 clock cycle If data is not found in the cache, 80 clock cycles are needed to get it from off- chip memory Designers are trying to improve the average memory access time to...
Base machine has a 2.4GHz clock rate. There is L1 and L2 cache. L1 cache is 256K, direct mapped write through. 90% (read) hit rate without penalty, miss penalty is 4 cycles. (cost of reading L2) All writes take 1 cycle. L2 cache is 2MB, 4 way set associative write back. 95% hit rate, 60 cycle miss penalty (cost of reading memory). 30% of all instructions are reads, 10% writes. All instructions take 1 cycle - except reads which take...
(a) Given a 100 MHz machine with a with a miss penalty of 20 cycles, a hit time of 2 cycles, and a miss rate of 5%, calculate the average memory access time (AMAT). (b) Suppose doubling the size of the cache decrease the miss rate to 3%, but causes the hit time to increases to 3 cycles and the miss penalty to increase to 21 cycles. What is the AMAT of the new machine?
Q44 Consider a memory with features in Table Q44 (a) and Table Q44 (b). Memory Type Level 1 cache Level 2 cache Level 3 cache DDR SDRAM Hard disk Table Q44 (a) Clock Cycle 2 6 8 143 178 Table Q44 (b) Item Total Number of L2 Cache accessed by CPU Total Number of Hit Hit Time Value 50 access 45 access 7 ns (a) By using the features as in Table Q44 (a), determine the miss penalty in nanoseconds...
Question 4 (10 pt). One difference between a write-through cache and a write-back cache can be in the time it takes to write. During the first cycle, we detect whether a hit will occur, and during the second (assuming a hit) we actually write the data. Let’s assume that 50% of the blocks are dirty for a write-back cache. For this question, assume that the write buffer for the write through will never stall the CPU (no penalty). Assume a...
Systems Programming problem: Consider a processor with the following parameters Base CPI (no Memory Stall) Clock rate L1 miss rate L2 Direct Mapped speed L2 Direct Mapped miss rate L2 8-way set associative speed L2 8-way set associative miss rate 1. 1.5 2 GHz 12 cycles 3.5% 28 cycles 1.5% Main Memory Access Time = 50 ns Calculate the CPI with L1 only * Calculate the CPl with L1 and L2 Direct Mapped Calculate the CPI with L1 and L2...
Exercise 8.16 You are building a computer with a hierarchical memory systenm that consists of separate instruction and data caches followed by main memory. You are using the ARM multicycle processor from Figure 7.30 running at 1 GHz (a) Suppose the instruction cache is perfect (i.e., always hits) but the data cache has a 5% miss rate. On a cache miss, the processor stalls for 60 ns to access main memory, then resumes normal operation. Taking cache misses into account,...