Question

Complete 1. Create a function to solve the Quadratic Formula as know as ax +bx+cwit solution is 2a The function must have only 3 reference parameters which are the coefficient of the quadratic equation a, b and c, at the end the function must return the real value of x. If a-0, or there is a negative root square obtained, the function must sent a message error to the user The coefficient of it can't be equal zero" or "Negative root solution are Founded Sorry try again 2. For this problem you need to use the following algorithms tools already learned on previous modules such as PAC, IPO, flow charts, and the new technic learned on this module such as Coupling interactivity chart diagram, Data Dictionary. Test your result using the following data let a#1 b-2 c-1, let a-4 ,b 3, c-1, and let a-0 b-3,C-2

Answer 1

a x^2 + bx + c = 0 x^2 + b/a x + c/a = 0 (Divide by 'a') (x^2 + b/a x + b^2/y a^2) + (c/a - b^2/ya^2) = 0 (x + b/2a)^2 + 4ac - b^2/4a^2 = 0 (x + b/2a)^2 = b^2 - 4ac/4a^2 (x + b/2a)^2 = b^2 - 4ac/4a^2 (x + b/2a) = plusminus squareroot b^2 - 4ac/4a^2 x = -b/2a plusminus squareroot b^2 - 4ac/2a x = -b plusminus squareroot b^2 - 4ac/2a If a = 0, then we can't follow this rule For a = 1, b = 2, c = 1 we have x^2 + 2x + 1 = 0 x = -2 plusminus squareroot 2^2 - 4 (1) (1)/2 (1) x = -2 plusminus squareroot 4 - 4/2 = -2 plusminus 0/2 x = -1, - 1 For a = 4, b = 3, c = 1, we have 4x^2 + 3x + 1 = 0 implies x = -3 plusminus squareroot