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1. Use both circuits and incorporate a carry in using basic gates to get a 1 bit full adder.

2. Using the prior circuit, modify it to make a 3 bit adder that can add the two’s complement of the 2nd input (i.e. be able to subtract).

I have drawn two gates, one is used to (i)"calculate the sum of two bits using basic gates." while the other is used to (ii)"carry out for the sum of two bits using basic gates. (No Cin)"

Here they are

(i)A B c0 000 0 0 1 0 1 1 0 1 0 0 1 1

(ii)B


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Answer #1

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Steb-t = 3 bit Binazy Added with 2s complement of 2nd 1/4 Istip 2nd ILP A A A 2 2 1 ? -Cin 2s complement of B 35 bit BA (BiStep2 A₂ B 8. н. 1 FA FA FA Carry ♡ 3bit Binary Adder with 2s complement ♡ Expand foom of stebtStep3: Full addeo is made with those basic gates which is encapsulated in box A -S=sum -C = Carry Full adder

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