|
worker |
time |
|
1 |
95 |
|
2 |
23 |
|
3 |
43 |
|
4 |
37 |
|
5 |
82 |
Answer a: Labor content = sum of task time =95+23+43+37+82 = 280 secs
Worker 1 is the bottleneck of the process, because worker 1 takes 95 secs to perform his tasks. Its process capacity is 60/95= 0.63 units per min or 37.89 units per hour
Direct labour cost per unit = total wages per hour/ units per hour
wages per hour= $ 24
Answer b: Direct labour cost per unit = $24*5/37.89 =$3.17 per toothbrush
Answer c: cycle time= 95 secs, idle time for worker A= 0 secs
labor utilization worker A= effective cycle time/cycle time of the system= 95/95= 1.0
Answer d: idle time= bottleneck time- process time
|
worker |
process time |
idle time= 95-process time |
|
1 |
95 |
0 |
|
2 |
23 |
72 |
|
3 |
43 |
52 |
|
4 |
37 |
58 |
|
5 |
82 |
13 |
|
Total |
280 |
195 |
Average labour utilization= 280/(280+195)= 0.59
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