Question

Q1. Based on a 2014 report from a consortium called GIANT (Genetic Investigation of Anthropometric Traits), it has been reported that there are at least 424 genes that contribute to determining the polygenic trait, height, in humans. Assuming there are two alleles for each gene, how many unique phenotypes would be generated? U ow 424 425 848 849 6.023 x 10 Q2. In fruit flies, the y+ and ct+ genes are located on the X chromosome. Grey body color is controlled by the y+ gene, which is dominant to the y allele, which results in a yellow body phenotype. Normal wing phenotype is controlled by the ct+ gene, which is dominant to the ct allele, which results in a cut wing phenotype. Two pure-breeding parents were crossed to generate the F1 males & females. The females are heterozygous for these two genes. The heterozygous F1 females are crossed to the F1 males to generate the F2 progeny. The phenotypes and the progeny numbers of the F2 MALES are shown in Table 3-1: phenotype progeny y ct 35 recombinant y+ ct 225 parental y ct+ 203 parental ly+ ct+ 37 recombinant total progeny 500 total progeny Table 3-1. Results of the male F2 progeny of the F1 intercross. Using the data provided in Table 3-1, what is the map distance between the y gene and ct gene? A. Uow 5.2 CM 14.4 CM 47.6 CM 48 CM 52.4 CM

Answer 1

Answer 1:

The number of genes encodes a phenotype are 424.

The number of phenotype is calculated by:

2× n +1

n= number of genes= 424

Unique phenotype:( 2× 424) + 1= 849.

Right answer is D (849)

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Answer 2)

The distance between y and ct gene is calculated by following formula= [ recombinant number/ total number]×100

=[ (35+37) /500]×100

=(72/500) ×100

=14.4 cM

right answer is b (14.4)

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