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wmlwm White eye Miniature wing w m/YO Red eye Full wing W W m wmlwm Red eye Full wing wm/Yd White eye Miniature wing Phenotyp

10) What is/are the parental phenotypic type(s) you predict in the F2 (progeny of the F1 cross)?

11) What is/are the recombinant type(s) you predict in the F2 (progeny of the F1 cross)?

12) Now that you can distinguish parental vs recombinant types, you can calculate the recombination between w+ and m+:

write the fraction and calculate the recombination frequency:

number of recombinant types       

_______________________ = ___________ =

Total number of progeny                

Now express the recombination frequency in centimorgans:

13) what would be the expected numbers for each phenotypic class in the F2, if the genes were UNLINKED? HINT: think of what would happen if w+ were on an autosome, with the same F1 parental cross.

14) Let us do a chi square analysis to see if the numbers obtained in figure 15.3 hold up.

Our hypothesis will be: THERE IS NO GENETIC LINKAGE between w+ and m+

- how many degrees of freedom? Why?

- write down the chi square equation: for each category, add (observed-expected)2

___________ +   ___________   +    ___________   +       __________

-the chi square result is 169.79

-look at the provided Table:

do you reject or accept the null hypothesis?  

Do you think the observed results deviate from the expected numbers for the null hypothesis?

-do you think the observed numbers support linkage between w+ and m+?

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Answer: The parental phenotype » Red eye I number Full wing ② White eye Inne in the fa progeny: of organisms : 791 numb minia

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