What are the expected phenotypic ratios of the F1 and F2 progeny assuming that your parental...
What are the expected phenotypic ratios of the F1 and F2 progeny assuming that your parental mutant stocks (P1 and P2) are: P1 carries recessive alleles for the trait of interest and P2 carries dominant alleles for that trait?
Homework Answers
Suppose plant length is controlled by a gene. A allele is responsible for tall phenotype, whereas a allele is responsible for short phenotype. P1 has genotype of aa, P2 has genotype of AA.
Expected phenotypic ratio in F1 will be all tall; expected phenotypic ratio in F2 will be tall: short = 3:1
Add Answer to:
What are the expected phenotypic ratios of the F1 and F2 progeny
assuming that your parental...
10) What is/are the parental phenotypic type(s) you predict in the F2 (progeny of the F1...
10) What is/are the parental phenotypic type(s) you predict in
the F2 (progeny of the F1 cross)?
11) What is/are the recombinant type(s) you predict in the F2
(progeny of the F1 cross)?
12) Now that you can distinguish parental vs recombinant types,
you can calculate the recombination between w+ and m+:
write the fraction and calculate the recombination
frequency:
number of recombinant
types
_______________________ = ___________ =
Total number of
progeny
Now express the recombination frequency in centimorgans:
13)...
The results for the F2 progeny are shown for a F1 cross using the two X-linked...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
with brown fur and all offspring had black fur. ne of the resulting F2 progeny were...
with brown fur and all offspring had black fur. ne of the resulting F2 progeny were brown 7. A guinea pig with black fur was bred to one with brown fur and all offspring na When two of these F1 offspring were bred, some of the resulting F2 progeny while others were black. a. What is the dominant phenotype? How do you know?__ b. Create symbols to represent the alleles for coat color in guinea pigs. Black = Brown =...
Two peanut cultivars are crossed and their f1 progeny are selfed to obtain an F2 generation....
Two peanut cultivars are crossed and their f1 progeny are selfed
to obtain an F2 generation. The first variety (represented in well
B) has a hairy stem. The second variety (represented in well C) has
a glabrous (hairless) stem. This trait is controlled by a single
gene, and hairy stems are completely dominant over hairless stems.
The DNA from both parents and the progeny is isolated, and a
portion of the gene controlling this trait is amplified using PCR
and...
The agouti locus in mice has three alleles a, A and AY. Use the following cross...
The agouti locus in mice has three alleles a, A and AY. Use the following cross results to answer the following questions. P: aa (black) x AA (agouti) --> F1: all agouti --> F2: 3 agouti : 1 black P: AYa (yellow) x AYa (yellow) --> F1: 2/3 yellow : 1/3 black P: AA (agouti) x AAY(yellow) --> F1: 1/2 agouti : 1/2 yellow a) The AY allele is dominant for yellow coat color. (Click for List) True False b)...
In a cross between a black and a white guinea pig, all members of the F1...
In a cross between a black and a white guinea pig, all members of the F1 generation are black. The F2 generation is made up of approximately 3/4 black and 1/4 white guinea pigs. A. Based on this cross, which trait is dominant and which is recessive? What information lead you to your conclusion? B. Diagram this cross, showing the genotypes and phenotypes of parental, F1 and F2 generations. C. What will the offspring be like if two F2 generation...
46. (7 points) Vanessa has obtained two true-breeding strains of mice, each homozygous for an independently...
46. (7 points) Vanessa has obtained two true-breeding strains of
mice, each homozygous for an
independently discovered recessive mutation that prevents the
formation of hair on the body.
One of the mutant strains is called naked, and the other mutation
strain is called hairless. To
determine whether the two mutations are simply alleles for the same
gene, Vanessa crosses
naked and hairless mice with each other (cross 1). All the
offspring are phenotypically wild-
type.
A) What is the most...
When red flowered snap dragons are mated with white flowered snap dragons, all of the F1...
When red flowered snap dragons are mated with white flowered snap dragons, all of the F1 progeny are pink. Assuming this trait is controlled by a single gene with two partially dominant alleles, what progeny would you expect if a pink flowered snap dragon were mated with a red flowered snap dragon? Draw a Punnett square to support your answer.
1. The presence of short hairs on the leaves of tomato plants is a dominant trait...
1. The presence of short hairs on the leaves of tomato plants is a dominant trait controlled by the allele H.The corresponding recessive trait, smooth leaf, is found in plants with the genotype hh. The table below shows the progeny of three independent crosses of parental plants with genotypes and phenotypes that are unknown. Number of Progeny Hairy Leaf Smooth Leaf Cross 1: Cross 2: Cross 3: 32 42 45 24 Examine the distributions of phenotypes in the progeny of...
Equations: p + q = 1 p 2 + 2pq + q 2 = 1 Three-way cross [(P1 x P2) x P3] predicted from F1's: 1/...
Equations: p + q = 1 p 2 + 2pq + q 2 = 1 Three-way cross [(P1 x P2) x P3] predicted from F1's: 1/2[F1(P1 x P3) + F1(P2 x P3)] Double cross [(P1 x P2) x (P3 x P4)] predicted from F1's: 1/4[F1(P1 x P3) + F1(P1 x P4) + F1(P2 x P3) + F1(P2 x P4)] V p = V A + V E + V D V G = V A + V D V E...
10) What is/are the parental phenotypic type(s) you predict in
the F2 (progeny of the F1 cross)?
11) What is/are the recombinant type(s) you predict in the F2
(progeny of the F1 cross)?
12) Now that you can distinguish parental vs recombinant types,
you can calculate the recombination between w+ and m+:
write the fraction and calculate the recombination
frequency:
number of recombinant
types
_______________________ = ___________ =
Total number of
progeny
Now express the recombination frequency in centimorgans:
13)...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
with brown fur and all offspring had black fur. ne of the resulting F2 progeny were brown 7. A guinea pig with black fur was bred to one with brown fur and all offspring na When two of these F1 offspring were bred, some of the resulting F2 progeny while others were black. a. What is the dominant phenotype? How do you know?__ b. Create symbols to represent the alleles for coat color in guinea pigs. Black = Brown =...
Two peanut cultivars are crossed and their f1 progeny are selfed
to obtain an F2 generation. The first variety (represented in well
B) has a hairy stem. The second variety (represented in well C) has
a glabrous (hairless) stem. This trait is controlled by a single
gene, and hairy stems are completely dominant over hairless stems.
The DNA from both parents and the progeny is isolated, and a
portion of the gene controlling this trait is amplified using PCR
and...
46. (7 points) Vanessa has obtained two true-breeding strains of
mice, each homozygous for an
independently discovered recessive mutation that prevents the
formation of hair on the body.
One of the mutant strains is called naked, and the other mutation
strain is called hairless. To
determine whether the two mutations are simply alleles for the same
gene, Vanessa crosses
naked and hairless mice with each other (cross 1). All the
offspring are phenotypically wild-
type.
A) What is the most...
1. The presence of short hairs on the leaves of tomato plants is a dominant trait controlled by the allele H.The corresponding recessive trait, smooth leaf, is found in plants with the genotype hh. The table below shows the progeny of three independent crosses of parental plants with genotypes and phenotypes that are unknown. Number of Progeny Hairy Leaf Smooth Leaf Cross 1: Cross 2: Cross 3: 32 42 45 24 Examine the distributions of phenotypes in the progeny of...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 11 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 11 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 11 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 11 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 11 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 11 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 11 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 11 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 11 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 11 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 11 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 11 months ago