Question

C++ Program

Your program should:

1) Validate that the number of commandline arguments, after a.out is in the range [1,6]. If not, print an error message and stop the program with exit code 1.

2) Declare a vector of ints or array of ints to store the arguments. Use a loop to parse all the arguments (except a.out) into your vector/array.

3) Use a loop to calculate the greatest number (maximum). If the maximum is greater than 100, print "XNN" on it's own line.

4) Use a loop to add together the numbers that are greater than 10. That means that numbers less than or equal to 10 are skipped for the purpose of adding. If this sum (the result of adding) is greater than 50, print "NNX" on its own line.

5) Use a loop to determine whether the last number appears again; in other words, determine whether the last number is duplicated. If so, print "ow" on its own line.

Answer 1

#include <iostream>

#include <vector>

#include <string.h>

using namespace std;

int main(int argc, char *argv[])

{

    // 1) Validate that the number of commandline arguments,

    // after a.out is in the range [1,6].

    // If not, print an error message and stop the program with exit code 1.

    if (argc < 2 || argc > 7)

    {

        cout << "Error! please enter 1 to 6 integers.\n";

        return 1;

    }

    // 2) Declare a vector of ints or array of ints to store the arguments.

    vector<int> array;

    // Use a loop to parse all the arguments (except a.out) into your vector/array.

    for (int i = 1; i < argc; i++)

    {

        // convert to int and add

        array.push_back(atoi(argv[i]));

    }

    // 3) Use a loop to calculate the greatest number (maximum).

    int max = 0;

    for (int i = 0; i < array.size(); i++)

    {

        if (array[i] > max)

            max = array[i];

    }

    // If the maximum is greater than 100, print "XNN" on it's own line.

    if (max > 100)

        cout << "XNN\n";

    // 4) Use a loop to add together the numbers that are greater than 10.

    // That means that numbers less than or equal to 10 are skipped for the purpose of adding.

    int sum = 0;

    for (int i = 0; i < array.size(); i++)

    {

        if (array[i] > 10)

            sum += array[i];

    }

    // If this sum (the result of adding) is greater than 50, print "NNX" on its own line.

    if (sum > 50)

        cout << "NNX\n";

    // 5) Use a loop to determine whether the last number appears again;

    // in other words, determine whether the last number is duplicated.

    for (int i = 0; i < array.size() - 1; i++)

    {

        if (array[i] == array[array.size() - 1])

        {

            // If so, print "ow" on its own line.

            cout << "ow\n";

            break;

        }

    }

    return 0;

}

Output:

PS D:\fixer> . \a.exe 332 XNN NNX PS D:\fixer> .\a.exe 100 NNX PS D:\fixer> .\a.exe 40 10 PS D:\fixer> .\a.exe 40 32 NNX

.