Question

Find the minimum angular separation resolvable with 625nm laser light passing through a circular aperture of diameter 2.2cm .

Express your answer using two significant figures.

Answer 1

D sin theta = 1.22L

sin theta = 1.22* 625nm/0.022

sin theta = 3.46 *10^-5

theta = 0.00198 deg

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Answer 2

We use ??1.22?/D, where ? is the angular separation, ? is the wavelength, and D is the aperture diameter. Plugging in the given values, we get ??1.22*(6.25*10^-7)/(0.022) ? 3.46*10^-5 radians