Question

Question 4 (1 point) Given the following reaction, what is the AGC for the spontaneous reaction in kJ/mol? Faraday's constant = 96500 Coulomb/mol (96.5 kJ/ mol) Round your answer to the nearest whole number i.e. if you calculated 52.02, input your answer as 52). IF YOUR ANSWER IS A NEGATIVE VALUE MAKE SURE TO INCLUDE THE NEGATIVE SIGN. IF IT IS POSITIVE YOU CAN LEAVE IT AS IS. NAD+ + H+ + 2e + NADH NO3 + 2H+ + 2e + NO2 + H20 E'o= -0.320V E'o= 0.421 V Question 5 (1 point) If one mole of laurate undergoes complete beta oxidation, it will produce mol of Acetyl-CoA, mol of NADH and mol of FADH2.

Answer 1

NADH ------------> NAD^+ + H^+ + 2e^-            E0 = 0.320v

NO3^- + 2H^+ +2e^- ------> NO2^- + H2O        E0 = 0.421v

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NADH + NO3^- + H^+ ------------> NAD^+ + NO2^- + H2O   E0cell = 0.741v

n = 2

$\Delta$ G0    = -nE0cell*F

              = -2*0.741*96500

             = -143013J/mole

            = -143KJ/mole >>>answer

8 mol of Acetyl-CoA

24 mol of NADH

8 mol of FADH2