Question

13. A 1/2, fourfold serial dilution was performed. The original concentration of the analyte was 1200 μg/dL. What is the concentration of the analyte in the final tube?

7. Calculate the true analyte value given the following information: Analyte diluted using 10 μL into 90 μL diluent; Diluted analyte value = 85 mg/dL.

Answer 1

Answer to the problem: 13. Initial concentration of analyte = 1200 Mg Jola Afler half dilution the final concentration of any solutie be half of the original concentration of the solution: ation Four,fold serial ditutat dilution; lep: I Let us make a solution containing 5 ml H₂O and 5 ml of analyte. . Final volume = 10 ml Visi = V₂ S2 V = Initial volume of analylē S = Initial con E of analyte or 5x1200 mg/dl = 10 x 6₂ Y = Final volume of analyté a 5. = 5x1200 ug/al S = Final Conch of analyte y = 5 ml, S. = 1200 uglah a 5 = 600 mg/dL V2 = 10 m, S₂ = ? Step : 3 1,5 = ½ S2 or 5x600 mg/dl. = 10x6₂ or S2 = 5x 600 rug/dL V = 5 ml. Si = 600 mg/dL V2 = 10 ml 10 " Sa 300 ng/di Step 3 Ys, = V₂ S2 V = 5 ml Si = 300 ug/aL V2 = 10 ml S2 = 2 ar 5x 300 Mg/dL = 10xS₂ a, 5 54,300 ng lal a s2 = 150 mg/dl

Step: 4 or a a vs, = V252 5x150 mg/l = 10xS2 Sze 5x150 ugfal = To ng lal V = 5ml V = 10ml si = 150 Mg/ml S = ? i. The final concentration of the analyte after four fold dilation is 75 mg/dl. : Ans. Analyte volume = 10 ML Di lwent volume = gou : Final volume = 100/ul Final Concentration = 85 mg/dh - i vise in Ve S2 on 10x.5, = 100x 85 mg/aL si = 1084 85 mald or = Initial volume = Initial conce = Final volume Si Final con Å VE 10 M, S,=? V = 100 u, 52 = 85 mg/dL i Final To mg/dL a. s,= 850 mgfal :. True analyte value is 850 mglal.