RrYyCc x RrYyCc is a trihybrid cross. what is the probability of having a progeny with...
RrYyCc x RrYyCc is a trihybrid cross.
what is the probability of having a progeny with all heterozygous genotype?
Homework Answers
Genotype- Rr Yy Cc x Rr Yy Cc
(for homozygous genotype probability is 1/4 and for heterozygous it will be 2/4)
Hence, 2/4*2/4*2/4=8/64
i.e. 1/8
1/8 progeny with all heterozygous genotype
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RrYyCc x RrYyCc is a trihybrid cross.
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