If you are making a 1:10 dilution of a 10mg/ml BSA solution using 90ul of water...
If you are making a 1:10 dilution of a 10mg/ml BSA solution using 90ul of water as diluent, how much 10mg/ml of BSA would you add? What would be your final concentration of BSA? If you assayed both these solutions using the Bradford assay which one would have a higher O.D.?
Homework Answers
I suppose ul means microliter (
).
Let's analyze what a dilution is, when you say it is 1:10 diluted,
it means that 1 part out of ten parts is the original sample, so to
make a 1:10 dilution you have to add 9 part of water and 1 part of
sample. We already have the water which is 90ul, then we have to
add 10ul of sample to achieve the given 1:10 dilution.
how much 10mg/ml of BSA would you add? 10ul of such original sample
What would be your final concentration of BSA? For this we have to transform the units.
We have 0.01mg BSA per 100 ul that we prepared, that is (0.01mgBSA)/(100ul) = 0.00001mgBSA/ul
If you assayed both these solutions using the Bradford assay which one would have a higher O.D.?
The optical density value won't vary with the concentration of the same compound, both dilutions will use the same o.d. value
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