Question

1. You want to prepare a 1:50 dilution of your protein extract in a total volume of 1000 uL. You will need ___ uL of protein extract and ___ uL of water.

2. You are provided with a solution of BSA that is 100 ug/mL and make a 10^-2 dilution? What is the resulting concentration of the DILUTED BSA?

3.

Which of the following statements about enzymes is true?

Select one:

a. Enzymes increase the rate of a chemical reaction by raising the activation energy for the reaction

b. Enzymes react with their substrate (form chemical bonds), forming an enzyme-substrate complex, which irreversibly changes the enzyme

c. Enzymes work equally well at any temperature

d. Enzymes can typically bind many types of substrates

e. None of the above

4. A Bradford assay is one application of using a “standard curve.” One uses known concentrations of BSA (and their measured absorbance at 595 nm values) to calculate unknown concentrations of some solution of interest (i.e. our protein extract). For example, you measure the absorbance readings of known concentrations of BSA and make a “y vs. x” plot: Absorbance at 595 nm vs. Concentration (ug/mL). You obtain a regression equation of y = 0.096x + 0.0286. Suppose the Abs₅₉₅ reading of a 1:10 dilution of a protein extract was 0.26. What is the protein concentration of the UNDILUTED protein extract?

Please answer all

Answer 1

QUESTION 1 In order to determinate how much protein you need to make a dilution 1:50 of 1000 ul, divide 1000 ul by 50 parts You need to dilute 20 uL of the 1000 L protein in 980 uL of water - = 20 L 50 QUESTION 2 For this, just multiply the initial concentration of BSA by the dilution factor 100 ug/mL x 10-2 = 10 ug/mL Note: According to Chegg's guidelines, you have to send just one question. Please, send each question separate so all experts can answer each of your questions. Thank you!.