Given
R = 68 m
theta = 21.4
speed v = 26.4 m/s
from the relation
tan(theta) = (v^2 -( mue * R * g)) / (mue *v^2 + (R * g))
tan(21.4) = (26.4^2 -(mue * 68 * 9.8)) / ( mue * 26.4^2 + (68 *
9.8))
mue = 0.46
A highway curve of radius 68.0 m is banked at 21.4 degree so that a car...
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PLEASE ANSWER PART B.
THANKS!
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