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Consider the following gas-phase equilibrium reaction: N (6) + O2(g) + 2NO(g); K. - 4.10 x 10 at 2000°C If 1.0 mol of NO is i

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Answer #1

Solution Given reaction is Na (g) + O2(g) - 2 NO igs - The equilibrium constant can be written as Kc = [NO]2 - 4.10x10h – [N2Now, equilibrium constant can be written as. = [N2] [O] [no] ke e.x 1-2x)2 » - (from egr®) 2.44 x103 = x² (1-2x32 x 20.27 m.

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