Consider the circuit shown in (Figure 1). The batteries have emfs of Ei = 9.0 V...

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Consider the circuit shown in (Figure 1). The batteries have emfs of Ei = 9.0 V and Ex = 12.0V and the resistors have values

Consider the circuit shown in (Figure 1). The batteries have emts of Ei = 9.0 V and Ex = 12.0V and the resistors have values

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Answer 1

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R = 272 % QV - E Using Kirchhoffs laws For loop ABC FA I, R, + J₂ R2 -&=0 R2=64 sy FH 12V - & (271, +64 22 - 920) E R₂ = 41 we have 0 & ② as 271, +647 = 9 ]X41 - U11 + 1051 = 12 ] x 27 1107 1; + 26241, - 369 - 1107 I, +2835 I₂ = 324 5459 I 2 = 693 3

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