Question

All solutions must have both code and data segments

1. Write a sequence of assembly language instructions to subtract each entry of an array B of five two’s complement 16-bit binary integers from the corresponding entry of an array A of five two’s complement 16-bit binary integers and construct a third array C of two’s complement 16-bit binary integers. i.e. C[i] = A[i] - B[i].

Use the following data for the arrays A and B.

            A: 10, -15, 20, 4, -5

            B: 25, -5, -30, 6, 10

2. Rewrite the assembly language instructions of question 1 for DEBUG environment.

3. Write a sequence of assembly language instructions to subtract 5 to each zero or positive entry and add 3 from each negative entry in an array A of 10 word two's complement binary integers.

Use the following data for array A: 6, 10, 25, -5, -30, 4, -5, 10, -15, 0

Answer 1

class GFG
{
  
// Returns '0' for '1' and '1' for '0'
static char flip(char c)
{
return (c == '0') ? '1' : '0';
}
  
// Print 1's and 2's complement of binary number
// represented by "bin"
static void printOneAndTwosComplement(String bin)
{
int n = bin.length();
int i;
  
String ones = "", twos = "";
ones = twos = "";
  
// for ones complement flip every bit
for (i = 0; i < n; i++)
{
ones += flip(bin.charAt(i));
}
  
// for two's complement go from right to left in
// ones complement and if we get 1 make, we make
// them 0 and keep going left when we get first
// 0, make that 1 and go out of loop
twos = ones;
for (i = n - 1; i >= 0; i--)
{
if (ones.charAt(i) == '1')
{
twos = twos.substring(0, i) + '0' + twos.substring(i + 1);
}
else
{
twos = twos.substring(0, i) + '1' + twos.substring(i + 1);
break;
}
}
  
// If No break : all are 1 as in 111 or 11111;
// in such case, add extra 1 at beginning
if (i == -1)
{
twos = '1' + twos;
}
  
System.out.println("1's complement: " + ones);;
System.out.println("2's complement: " + twos);
}
  
// Driver code
public static void main(String[] args)
{
String bin = "1100";
printOneAndTwosComplement(bin);
}
}