Question

Write a C program that runs on ocelot for a mini calculator using only the command line options.

You must use getopt to parse the command line. Usage: minicalc [-a num] [-d num] [-m num] [-s num] [-x] value 

The variable value is the starting value. 

Value should be validated to be an integer between 1 and 99. Error message and usage shown if not. 

For all options num should be a positive integer between 1 and 20. 

-a adds num to value. 

-d divides value by num. 

-m multiplies value by num. 

-s subtracts num from value. 

-x squares value. (Note: no num is needed.)

 Output should have exactly 2 decimal places no matter what the starting values are. 

If –x is included, it is executed first. 

There will be at most one of each option, if there are more than one you can use either of the options in the calculation. 

Use standard order of operations for all operations.

Answer 1

#include<stdio.h>

int main (){

int var;
printf("Enter the value of variable between 1 and 99: ");

scanf("%d",&var);

if( var <= 1 || var >= 99){
printf("Variable must be between 1 and 99");
return 0;
}

int op;
printf("Enter the options from a (1), d (2),m (3),s (4) and x (5) : ");

scanf("%d",&op);

if(op == 5){
printf("result = %d",var*var);
}
else{
int num;
printf("Enter the num: ");
scanf("%d",&num);
int result;
if(op == 1)
result = num + var;
else if(op==2)
result = var/num;
else if(op==3)
result = var*num;
else
result = var-num;

printf("result = %d",result);

}

return 0;
}

DAChegglq6.exe Enter the value of variable between 1 and 99: 58 Enter the options from a (1), d (2),m (3),s (4) and x (5)3 Enter the num 3 result 174 Process returned 0 (0x0excution time9.392 s Press any key to continue