The production manager thinks that the humidity is
affecting the production rate as it increases. Using an alpha of 5%
determine if humidity affects the rate of production.

Determine:
⦁ The Sum of Square for total variation
⦁ The Sum of Square for the treatment
⦁ The Sum of Square for the block
⦁ The Sum of Square for the intersection of block and treatment
⦁ The Sum of Square for the experiment errors
⦁ The Experimental F Temperature
⦁ The Experimental F Shifts
⦁ The Experimental F Temperature and Shifts
⦁ The Critical Value of F Temperature
⦁ The Critical Value of F Shifts
⦁ The Critical Value of F Temperature and Shifts
⦁ Based on the ANOVA: what conclusion should be taken for Temperature:
-Significant impact for the temperature and shifts
-Significant impact for the temperature
-No significant impact of the temperature
-None of the above
⦁ Based on the ANOVA: what conclusion should be taken for shifts:
-Significant impact for the temperature and shifts
-Significant impact for the shifts
-No significant impact of the shifts
-None of the above
⦁ Based on the ANOVA: what conclusion should be taken for both:
-Significant impact for the temperature and shifts
-Significant impact for the temperature only
-No significant impact of the temperature and shifts
-None of the above
By using MINITAB,
MTB > GLM;
SUBC> Response 'responce';
SUBC> Nodefault;
SUBC> Categorical 'Temperature' - 'shift';
SUBC> Terms Temperature shift;
SUBC> TMethod;
SUBC> TAnova;
SUBC> TFactor.
General Linear Model: responce versus Temperature,
shift
Factor Information
Factor Type Levels Values
Temperature Fixed 3 70, 80, 90
shift Fixed 2 1, 2
Analysis of Variance
Source DF Adj SS Adj MS F-Value P-Value
Temperature 2 8.167 4.083 0.19 0.834
shift 1 533.333 533.333 24.43 0.003
Temperature*shift 2 10.167 5.083 0.23 0.799
Error 6 131.000 21.833
Total 11 682.667
The Critical Value of F Temperature = F(df temperature , df error) = F(2,6) = 5.14
The Critical Value of F Shifts = F(df shifts , df error) = F(1,6) = 5.99
The Critical Value of F Temperature and Shifts = F(df temperature*shifts , df error) = F(2,6) = 5.14
From pvalue (Temperature) =0.834 > alpha = 0.05
Accept H0. No significant impact on Temperature.
From pvalue (Shifts) =0.003 < alpha = 0.05
Reject H0, Significant impact for the shifts
From pvalue (Temperature * Shifts) =0.799 > alpha = 0.05
Accept H0. No significant impact of the temperature and shifts.
The production manager thinks that the humidity is affecting the production rate as it increases. Using...
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· The impact from the Pressure
· The impact of the interaction of both variables
· The Experimental Error Deviation
· The Experimental T for Speed
· The Experimental T for Pressure
· The Experimental T for the variables interaction
· The Critical Value of T that will be used to compare
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