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21. Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A...

21. Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A 30 g bullet is fired at 500 m/s toward the blocks. It

21. Two 500 g blocks of wood are 2.0 m apart on a frictionless table. A 30 g bullet is fired at 500 m/s toward the blocks. It passes all the way through the first block, then embeds itself in the second block. The speed of the first block immediately afterward is 6.0 m/s. What is the speed of the second block after the bullet stops in it?
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Answer #1

Using law of conservation of momentum,

m1u1 + m2u2 = m1v1 + m2v2

30 x 500 = 500 x 6 + 30 v2

V2 = 400 m/s

Again using law of conservation of momentum,

500 v1 + 0 = 30 x 400 + 0

Velocity, v1 = 24 m/s

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