Question

C++. i have a function

bool get(int argc, char* argv[], option& opt)

./a.out -a123 -b 56s -call -0 -uabs these are the arguments

i want to erase the first character '-' and store the output in the option and value string variables.

output will be:

option: = a value : = 123

option: = b value: = 56s

option: = c value := all

option : = 0

option: = u value : = abs

Answer 1

Hello, please find the code, code snapshots and output snapshot below.

Code:

//standard c++ libraries
#include<bits/stdc++.h>
#include<string>
using namespace std;

//a c++ class for the string types
class option{
   public:
       string op, value;
};

//get function which is having three parameter values
bool get(int argc, char* argv[], option& opt){
   int i;
   for(i = 1; i < argc; i++){
       string s = argv[i];
       opt.op = s[1];
       opt.value = s.substr(2);
       if(opt.op != ""){
           cout<<"option: = "<<opt.op<<" ";
       }
       if(opt.value != ""){
           cout<<"value: = "<<opt.value;
       }
       cout<<endl;
   }
   return true;
}

//main method to call get method
int main(int argc, char* argv[]){
   option opt;
   get(argc, argv, opt);
   return 0;
}

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Code Snapshot:

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Output snapshot:

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