Question

Write a method that takes an array of ints and that returns true if there are more odd numbers than even numbers. However, as for a casino, 0 is not counted as an odd or an even number. If the array is empty or contains only 0's the method should return false.

Answer 1

public class MoreOddsThanEven {

    public static boolean moreOddsThanEven(int[] arr) {
        int evenCount = 0, oddCount = 0;
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] % 2 == 0) {
                evenCount++;
            } else {
                oddCount++;
            }
        }
        return oddCount > evenCount;
    }

    public static void main(String[] args) {
        System.out.println(moreOddsThanEven(new int[] {1, 3, 8, 6, 5}));
        System.out.println(moreOddsThanEven(new int[] {1, 3, 8, 6, 5, 4, 8}));
    }
}