A4.25 %w/v solution (4.25g per 100.0 mL) of starch in water was found to have an osmotic pressure of 82.7 mmHg at 303.6 kelvin. Calculate the average molar mass of the starch used, taking 1.00 atm = 760.0 mmHg. The value of the gas constant, R , is 0.0821 L atm K-1 mol-1. Present your answer as a numerical value only, to 3 significant figures in the form x.xxEx.
A4.25 %w/v solution (4.25g per 100.0 mL) of starch in water was found to have an...
A 5.24 %w/v solution (5.24g per 100.0 mL) of starch in water was found to have an osmotic pressure of 81.1 mmHg at 296.7 kelvin. Calculate the average molar mass of the starch used, taking 1.00 atm = 760.0 mmHg. The value of the gas constant, R , is 0.0821 L atm K-1 mol-1. Present your answer as a numerical value only, to 3 significant figures in the form x.xxEx.
100. mL of solution and is found to have an osmotic pressure of 28.1 mmHg at 20°C. Calculate the molar mass of the compound. (1 atm 760 mmHg) 1 0.102 g of an unknown non electrolyte solute is dissolved in enough water to make A. 663 g/mol B. 0.872 g/mol C. 1.15 g/mol D. 727 g/mol E. 1.10 x 102 g/mol
A solution of an unknown nonelectrolyte is formed by adding 1.13 g in 250 mL of water. This generates an osmotic pressure of 0.46 atm at 25 °C. Given R = 0.0821 L-atm/K-mol, calculate the molar mass of the nonelectrolyte (to two significant figures). Please explain step-by-step.
When 10.0 mg of sucrose is dissolved in enough water to make 100.0 mL of solution at 25.00 °C, an osmotic pressure of 5.43 mmHg is measured. What is the molar mass of sucrose? Show your work, and provide your answer in g/mol.
Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.45 g dissolved in 199.2 mL of water at 49.72 °C has an osmotic pressure of 34.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures.
Colligative Properties 1a When a solution is made from 25.9 g of an unknown nonelectrolyte dissolved in 167.6 g of solvent, the solution boils at 63.24 °C. The boiling point of the pure solvent and its Kb are 59.02 °C and 2.09 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. Report your answer to TWO places past the decimal 1b When a solution is made from 39.5 g of an unknown nonelectrolyte dissolved in 109.1-2.47 °C....
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
3a. Calculate the required mass of an unknown nonelectrolyte (ℳ = 125.7998 g/mol) dissolved in 129.7 g of solvent that gives a solution that freezes at 1.85 °C. The freezing point of the pure solvent is 4.44 °C and its Kf value is 1.87 °C/m. Report your answer to TWO places past the decimal. 3b. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.613 g dissolved in 250.3 mL of water at 19.47 °C has an osmotic...
2a Calculate the freezing point of a solution that is made from 39.9 g of a nonelectrolyte (ℳ = 142.4701 g/mol) dissolved in 186.3 g of solvent. The solvent freezes at 1.24 °C and its Kf value is 2.09 °C/m. Report your answer to TWO places past the decimal. 2b The solubility of carbon dioxide gas at 37.3 °C and a carbon dioxide pressure of 554 mmHg is 4.04 × 10−3 g/L. What is the Henry's Law constant in mol⋅L−1⋅atm−1?...
1315 atm 161 at 60.0 °C. What is the The vapor pressure of benzene is 100.0 mm boiling point of benzene at 760.0 mmHg? and 400.0 mm I 750 In Hvar ( ) 1:3768, ose 1.00 30016 - .0033416) . - AHUR (-3,4 x 10-4 ) 1,3868 8.3145 - 33.6)KT T - 4078-1235 12 100881425 8.8145 - 33411,3385 - A Hva 0 4099,667 Dlvy 33,91 11. Ethylene glycol CH OHCH,OH is a slightly viscous liquid and has boiling point of...