Answer all questions and explain in detail.
1) GAL80 loss-of-function mutants express GAL1, 2, 7, 10, genes constitutively (in the absence of galactose) because
| a | transcriptional activation by GAL4 is not inhibited |
| b | GAL80 is not present to block GAL4 DNA-binding |
| c | GAL80 cannot respond to GAL3 signaling |
| d | A and B |
| e | B and C |
2) Gal80-; GAL4- double mutants express the GAL1, 7, 10 genes
| a | only In the presence of galactose |
| b | only in the absence of galactose |
| c | never, whether galactose is present or not |
| d | always, whether galactose is present or not |
3) A yeast strain is defective in inducing GAL7 expression in response to galactose. The induction of GAL1, GAL2, and GAL10 was normal. This may be caused by a mutation in:
| a | GAL4 DNA binding domain |
| b | GAL4 activation domain |
| c | The UAS motif upstream of GAL7 |
| d | Any of the above |
| e | None of the above |
Answer 1: a
Explanation:
GAL4 is a transcriptional activator, which has two domains; a DNA binding domain, and an activation domain. In the absence of galactose, GAL80 mast the activation domain of GAL4 and inactivates it. GAL80 loss-of-function mutants produce non-functional GAL80, whcih can not mask the GAL4's activation domain, thus the related genes are constitutively expressed..
Answer 2: c
Explanation:
GAL4 and GAL80 double mutants cannot initiate transcription of GAL genes, as the GAL4 itself is inactivated and thus cannot activate transcription.
Answer 3: c
Explanation:
UAS (upstream activation sequence) is a cis-acting element, present upstream of the promoter of any gene and enhances the expression of that gene. If the UAS motif is defective, the related gene will not express. Thus, in the case of defective UAS of GAL7, GAL7 is not expressed but the other genes; GAL1, GAL2,and GAL10 are expressed.
Answer all questions and explain in detail. 1) GAL80 loss-of-function mutants express GAL1, 2, 7, 10,...
GAL80 loss-of-function mutants express the GAL1, 2, 7, 10 genes constitutively in the absence of galactose) because A. transcriptional activation by GAL4 is not inhibited B. GAL80 is not present to block GAL4 DNA-binding C. GAL80 cannot respond to GAL3 signaling D. A and B E. B and C TB 68
The yeast Saccharomyces cerevisiae can grow as haploid or diploid cells. You have two haploid yeast strains that each carry recessive mutations that affect regulation of the genes required for galactose metabolism. One strain has a deletion of the region of the genome on chromosome II that lies between the GAL1 and GAL10 genes (deltaUAS). The other strain carries a mutant allele of the GAL80 gene on chromosome XIII that produces no functional GAL80 protein. Which of the following correctly...
GAL4 null mutants express the GAL1, 2, 7 & 10 genes A. never whether galactose is absent or present B. constitutively whether galactose is absent or present C. only when galactose is present D. only when lactose is present E. only when galactose is absent 17 58
3. Assume presence of galactose and absence of glucose, and that mutants are loss of function. In a Gal 80 mutant, gal genes will/will not _________________ be expressed. In a gal4 mutant, gal genes will/will not ________________ be expressed. In a gal80/gal4 double mutant, the gal genes will/will not _________________ be expressed. If a scientist replaced the activation domain of gal4 with a histone deactylase domain, the gal genes will/will not ______________ be expressed.
I really need help with these questions!! 2. Bernard Davis tested the "cross-feeding" interpretation of some data that showed the phenotype of one microbe as capable of being changed by another microbe. His contribution can be summarized as: A) using one strain of microbes as food for another, and then evaluating the impact upon microbial phenotype. B) combining microbes with complementing auxotrophs in a single tube and then analyzing the cells of gene exchange. C) placing a barrier between bacterial...
A genetically engineered plasmid Ficarries all of the elements of the lac operon, but replaces the structural genes with the reporter gene green fluorescent protein (GFP). The repressor allele cannot bind lactose, and the OC allele cannot be bound by the repressor. Given the following genotypes and growth media that does not contain glucose, indicate in the table below whether you expect to see b-galactosidase activity and glowing green colonies of E. coli by selecting Yes or No. growth media...
Yet, all the cells in your body contain the same
genes (and same alleles). The difference across cell types
is that genes get selectively expressed (turned on or off)
based on the proteins needed for cellular function given their
environment.
Select which statement explains the reason why hair does not
normally grow on your muscle cells.
a.
Muscle cells have the gene for keratin, but do not express
it
b.
Muscle cells do not have the gene for keratin and...
explain figure 2 please on the third page
The Jounal of Immunol nes of the National Academy of Sciences USA 89. 6550-6554. 01992, by permision of Proc. Natl. Acad. Sci. USA Vol. 89, pp. 6550-63554, July 1992 Immunolog A 39-kDa protein on activated helper T cells binds CD40 and transduces the signal for cognate activation of B cells RANDOLPH J. NOELLE时, MEENAKSHI ROY.. DAVID M. SHEPHERD., IVAN STAMENKOVICt JEFFREY A. LEDBETTER, AND ALEJANDRO ARUFFo Departmend Microbiology. Dartmouth Medical School One...