C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...

Question

Question

C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...

C₆H₄(OH)₂(aq) + H₂O₂(aq) ----> C₆H₄O₂(aq) + 2 H₂O(l)

Given the entropies of the reactions below, calculate the entropy of the chemical explosion at 37 C.

2 H₂O_2
(aq) ------> 2H₂O(l) +O_2(g) = +0.4501 kj/mole*k

C₆H₄₍(OH)₂(aq) ------> C₆H₄O₂(aq) + H₂(g) = + 0.5033 kj/mole*k

2 H₂(g) + O₂(g) -----> 2 H₂O (l) = -0.327.2 kj/mole*k

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Similar Homework Help Questions

Consider the reaction: Ca(OH)2(aq) + 2HCl(aq) +CaCl(s) + 2H2O(1) Using standard absolute entropies at 298K, calculate...

Consider the reaction: Ca(OH)2(aq) + 2HCl(aq) +CaCl(s) + 2H2O(1) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.26 moles of Ca(OH)2(aq) react at standard conditions As system = JK Consider the reaction: 200(g) + O2(9)—*2002) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.60 moles of CO(g) react at standard conditions. ASºsystem ПІК
1) The enthalpy of formation for H2O(l) is given by H2(g) + 1/2 O2(g) → H2O(l)....

1) The enthalpy of formation for H2O(l) is given by H2(g) + 1/2 O2(g) → H2O(l). Add this reaction to H2O(l) + 1/2 O2(g) → H2O2(aq). This is the reverse of the decomposition reaction from this experiment. Show the sum of the above two reactions is the enthalpy of formation of H2O2(aq) 2) Calculate the literature value for the enthalpy of decomposition of H2O2(aq) from the enthalpies of formation of H2O2(aq), H2O(l) and O2(g) found in your textbook or any...
calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l)

calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ

13. Consider the reactions below; H2S(g) + H2O(1) H2S(g) + 2H2O(l) H30'(aq) + HS (ag); K1...

13. Consider the reactions below; H2S(g) + H2O(1) H2S(g) + 2H2O(l) H30'(aq) + HS (ag); K1 - 2.5 x 10 + 2H30 (aq) + (aq); K3 = 6.8 x 10-16 Use the information above to calculate the K for the reaction given below (6 points); HS (aq) + H2O(0) H:0 (aq) + (aq); K = ? 14. Consider the reaction below; 2NO2(g) + 2Cl2 2NOCl2(g) + O2(g) If the equilibrium constant Kat 100°C is 1.5 x 10, calculate its k....
1) Consider the reaction: P4O10(s) + 6H2O(l)------>4H3PO4(aq) Using standard absolute entropies at 298K, calculate the entropy...

1) Consider the reaction: P4O10(s) + 6H2O(l)------>4H3PO4(aq) Using standard absolute entropies at 298K, calculate the entropy change for the systemwhen 1.53 moles ofP4O10(s) react at standard conditions. S°system = J/K 1b) Consider the reaction: 2H2O2(l)--------->2H2O(l) +O2(g) Using standard absolute entropies at 298K, calculate the entropy change for the systemwhen 1.87 moles ofH2O2(l) react at standard conditions. S°system = J/K
Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e

Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq)2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq) Fe(s)⟶Fe2+(aq)+2e−Fe(s)⟶Fe2+(aq)+2e− oxidation reduction reduction oxidation reduction

Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change...

Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
1. Consider the reaction: H2CO(g) + O2(g)CO2(g) + H2O(l) Using standard absolute entropies at 298K, calculate...

1. Consider the reaction: H2CO(g) + O2(g)CO2(g) + H2O(l) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.41 moles of H2CO(g) react at standard conditions. S°system =___ J/K 2. For the reaction 3Fe2O3(s) + H2(g)>2Fe3O4(s) + H2O(g) DeltaH° = -6.0 kJ and DeltaS° = 88.7 J/K The standard free energy change for the reaction of 1.78 moles of Fe2O3(s) at 292 K, 1 atm would be ___ kJ. This reaction is (reactant, or product) favored...
Calculate the standard entropies for the following chemical reactions. Sulfur S(s, rhombic) 31.88 430.9 S818) 49.7...

Calculate the standard entropies for the following chemical reactions. Sulfur S(s, rhombic) 31.88 430.9 S818) 49.7 -300.4 SO2(8) SO;(8) SO2 (aq) 102.3 - 296.9 -395.2 -909.3 -370.4 -744.5 248.5 256.2 20.1 217.94 203.26 114.60 Hydrogen Hg) H(aq) H*(8) H2(8) 0 1536.2 1517.0 108.9 130.58 Iodine I(8) 1 (8) 106.60 -55.19 62.25 70.16 -51.57 19.37 12(8) 12(8) HI(g) 180.66 111.3 260.57 116.73 206.3 25.94 1.30 Entropy changes for a reaction can be estimated in a manner analogous to that by which...

H2O2(aq)⟶H2O(l) + 1/2 O2(g) a. The above chemical equation is for a first-order reaction. At 302...

H2O2(aq)⟶H2O(l) + 1/2 O2(g) a. The above chemical equation is for a first-order reaction. At 302 K , the rate constant equals 8.5×10−4s−1. Calculate the half-life at this temperature. Express your answer to two significant figures and include the appropriate units. b. If the activation energy for this reaction is 75 kJ/mol, at what temperature would the reaction rate be doubled? Express your answer as an integer and include the appropriate units.

C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...

Homework Answers

Request Answer!

Add Answer to:
C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...

Post as a guest

Earn Coins

Consider the reaction: Ca(OH)2(aq) + 2HCl(aq) +CaCl(s) + 2H2O(1) Using standard absolute entropies at 298K, calculate...

1) The enthalpy of formation for H2O(l) is given by H2(g) + 1/2 O2(g) → H2O(l)....

calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l)

13. Consider the reactions below; H2S(g) + H2O(1) H2S(g) + 2H2O(l) H30'(aq) + HS (ag); K1...

1) Consider the reaction: P4O10(s) + 6H2O(l)------>4H3PO4(aq) Using standard absolute entropies at 298K, calculate the entropy...

Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e

Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change...

1. Consider the reaction: H2CO(g) + O2(g)CO2(g) + H2O(l) Using standard absolute entropies at 298K, calculate...

Calculate the standard entropies for the following chemical reactions. Sulfur S(s, rhombic) 31.88 430.9 S818) 49.7...

H2O2(aq)⟶H2O(l) + 1/2 O2(g) a. The above chemical equation is for a first-order reaction. At 302...

C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...

Homework Answers

Request Answer!

Add Answer to: C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...

Post as a guest

Earn Coins

Add Answer to:
C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate...