You are attempting to launch your friend into the air using a see-saw: your friend stands...
You are attempting to launch your friend into the air using a see-saw: your friend stands on one end, and you will jump on the other, making him shoot up into the air. Where, relative to the center, should your friend stand? Where on the see-saw should you jump to maximize how high he goes?
Homework Answers
When I jump on the other side of see saw then angular velocity of each point on the other side will be equal but linear velocity depends upon the distance of pivot..So friend should be stand at the corner of see saw.
To give maximum moment to see saw I should also jump at the maximum distance from pivot since moment of force is proportional to the distance from pivot so I should also jump on the other end of see saw..
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You are attempting to launch your friend into the air using a
see-saw: your friend stands...
you are attempting to launch your friend Jim into the air using a see-saw: Jimstands on...
you are attempting to launch your friend Jim into the air using a see-saw: Jimstands on one end, and you will jump on the other, making him shoot up into the air. Where, relative to the center, should Jim stand? Where on the see-saw should you jump to maximize how high Jim goes? A drawing with arrowsindicating the positions is a sufficient answer.
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b) Assume that you are living in Dar es Salaam, Tanzania, and your friend, Safari, in Rwanda invites you to visit him. Safari is so generous, he has promised you to pay for your flight to Kigali to see him. The round-trip Dar - Kigali airfare costs $1,200. A week later, your other friend Mukai, from Nairobi hears from Safari that you will be going to Kigali. She also decides to invite you to come to see her in Nairobi...
(25%) Problem 4: You have been
hired to design a family-friendly see-saw. Your design will feature
a uniform board (mass M = 15 kg, length L = 11 m) that can be moved
so that the pivot is a distance d from the center of the board.
This will allow riders to achieve static equilibrium even if they
are of different mass, as most people are. You have decided that
each rider will be positioned so that his/her center of...
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