The standard deviation for an activity duration that can be represented by a Triangular distribution with...
The standard deviation for an activity duration that can be represented by a Triangular distribution with an optimistic duration of 5 days, most likely duration of 6 days and a pessimistic duration of 18 days is:
| A. |
8.72 |
|
| B. |
4.69 |
|
| C. |
2.95 |
|
| D. |
2.17 |
Homework Answers
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The standard deviation
for an activity duration that can be represented by a Triangular
distribution with...
Activity D on a PERT network has an optimistic duration of 3 days, a most likely...
Activity D on a PERT network has an optimistic duration of 3 days, a most likely duration of 5 days and a pessimistic duration of 13 days. What is the expected duration of activity D? Formula: Expected Activity time: t = (a + 4m + b)/6 a. 5 days b. 6 days c. 7 days d. 10 days e. 12 days
5. A project has critical path activities A, B, and C. A is the predecessor of B. B is the predec...
5. A project has critical path activities A, B, and C. A is the predecessor of B. B is the predecessor of C. The duration estimate for activity A, B and C is shown in the following table. Fill the table with mean duration, standard deviation, and variance for activities and the whole project (critical path). Determine what is the probability of completing this project within 80 days? (10 points) Activity Optimistic Pessimistic Most likely Mean Standard Variance deviation duration...
Please use the table to answer questions, SHOW WORK Consider the following work breakdown structure for questions 46-50: Duration (Days) Most Start Finish Activity Node Node Optimistic Likely Pessimi...
Please use the table to answer questions, SHOW WORK
Consider the following work breakdown structure for questions 46-50: Duration (Days) Most Start Finish Activity Node Node Optimistic Likely Pessimistic 50 31 70 41 35 59 34 82 41 58 32 30 5 46 What is the estimated expected (mean) time tor activity D? A 32 days B. 41 days C 44 days D. 42 days E 40 dayts 46 What is the estimated standard deviation for the critical path? A...
If the contracted duration for a project with the following network is 120 days, what is the prob...
If the contracted duration for a project with the following
network is 120 days, what is the probability (in percent) of
meeting the schedule based on PERT analysis? Then, assume that the
owner delays the start by 5 days while keeping the end date as
originally scheduled. What is the probability (in percent) that the
project will still finish at the originally scheduled completion
date? The requested probabilities should be determined based on the
entire network and not just one...
301247/mod_resource/content/B/Exam%202%20March%202020.pdf - + Fit to page Question 2) Use the table diagram below to answer the...
301247/mod_resource/content/B/Exam%202%20March%202020.pdf - + Fit to page Question 2) Use the table diagram below to answer the following questions? (20 Points) Time Estimates (days) Optimistic Most Likely Pessimistic Activity Start Precedes AB CD 56 D F F End a) Draw the project network? (5 Points) b) What is the expected duration and standard deviation for each activity? (5 Points) c) What is (are) the project critical path(s); duration(s); and standard deviation (s)? (5 Points) d) What's the probability that the critical...
4. A project has the following tasks and duration estimates given. These three tasks are done...
4. A project has the following tasks and duration estimates given. These three tasks are done in succession on a project. Task Optimistic Estimate Most Likely Estimate Pessimistic Estimate Alpha 30 days 40 days 50 days Beta 20 days 25 days 28 days Charlie 4 days 10 days 12 days Delta 25 days 30 days 50 days a. What is the expected duration for the project? (3 points) b. What is the variance for the project? (3 points) . c....
Using the Three-Point Estimating and Beta Distribution, what is the Expected Activity Cost if: (1) Most...
Using the Three-Point Estimating and Beta Distribution, what is the Expected Activity Cost if: (1) Most Likely Duration is 111 hours, (2) Optimistic Duration is 80 hours, and (3) Pessimistic Duration is 130 Hours? Assume a labor rate of $83/Hr. O $15,582 O $8,881 $6,664 O $4,984
Given the following activity list and times in days: (15 points) Activity Optimistic Most Likely Pessimistic...
Given the following activity list and times in days: (15 points) Activity Optimistic Most Likely Pessimistic Time Time Time A 7 10 12 B 6 8 14 C 5 9 12 D 12 14 21 E 10 12 15 F 4 5 8 G 1 3 8 H 12 15 17 NOTE 1: ASSUME THE CRITTCAL PATH IS “B-E-H”. Calculate the schedule duration of the critical path in days. What is the probability of the project being completed...
Assume all activities A, B, D are on the critical path. Activity Optimistic Time Most Likely...
Assume all activities A, B, D are on the critical path. Activity Optimistic Time Most Likely Time Pessimistic Time A 1 4 10 B 4 9 10 C 12 17 28 D 4 5 6 The expected time for activity B is? 18.0 4.5 8.33 6.17 What is the standard deviation for the project? 4.43 2.11 1.67 2.80
TIMES (days) Activity Start Node Finish Node OPTIMISTIC to MOST LIKELY tm PESSIMISTIC tp A 1...
TIMES (days)
Activity
Start Node
Finish Node
OPTIMISTIC
to
MOST LIKELY
tm
PESSIMISTIC
tp
A
1
2
24
30
42
B
1
3
20
23
32
C
2
5
15
27
39
D
3
4
25
43
61
E
4
5
15
42
69
Given the Activity on Arrow Diagram and the data found in the table
above, calculate each of the following values:
Activity A………te = 31
Standard Deviation = 3
Activity B………te =
Standard Deviation =
Activity C………te...
5. A project has critical path activities A, B, and C. A is the predecessor of B. B is the predecessor of C. The duration estimate for activity A, B and C is shown in the following table. Fill the table with mean duration, standard deviation, and variance for activities and the whole project (critical path). Determine what is the probability of completing this project within 80 days? (10 points) Activity Optimistic Pessimistic Most likely Mean Standard Variance deviation duration...
Please use the table to answer questions, SHOW WORK
Consider the following work breakdown structure for questions 46-50: Duration (Days) Most Start Finish Activity Node Node Optimistic Likely Pessimistic 50 31 70 41 35 59 34 82 41 58 32 30 5 46 What is the estimated expected (mean) time tor activity D? A 32 days B. 41 days C 44 days D. 42 days E 40 dayts 46 What is the estimated standard deviation for the critical path? A...
If the contracted duration for a project with the following
network is 120 days, what is the probability (in percent) of
meeting the schedule based on PERT analysis? Then, assume that the
owner delays the start by 5 days while keeping the end date as
originally scheduled. What is the probability (in percent) that the
project will still finish at the originally scheduled completion
date? The requested probabilities should be determined based on the
entire network and not just one...
301247/mod_resource/content/B/Exam%202%20March%202020.pdf - + Fit to page Question 2) Use the table diagram below to answer the following questions? (20 Points) Time Estimates (days) Optimistic Most Likely Pessimistic Activity Start Precedes AB CD 56 D F F End a) Draw the project network? (5 Points) b) What is the expected duration and standard deviation for each activity? (5 Points) c) What is (are) the project critical path(s); duration(s); and standard deviation (s)? (5 Points) d) What's the probability that the critical...
Using the Three-Point Estimating and Beta Distribution, what is the Expected Activity Cost if: (1) Most Likely Duration is 111 hours, (2) Optimistic Duration is 80 hours, and (3) Pessimistic Duration is 130 Hours? Assume a labor rate of $83/Hr. O $15,582 O $8,881 $6,664 O $4,984
TIMES (days)
Activity
Start Node
Finish Node
OPTIMISTIC
to
MOST LIKELY
tm
PESSIMISTIC
tp
A
1
2
24
30
42
B
1
3
20
23
32
C
2
5
15
27
39
D
3
4
25
43
61
E
4
5
15
42
69
Given the Activity on Arrow Diagram and the data found in the table
above, calculate each of the following values:
Activity A………te = 31
Standard Deviation = 3
Activity B………te =
Standard Deviation =
Activity C………te...
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