Question

Create a program that counts how many times a number is included in an array. To create the array ask for 10 values (as integers) and then ask for the number that should be checked for. Then print the number of times the requested number appears in the array (see below). Please comment your code as you go along. Hint: You may need 2 for loops for this, one to create your array and one to check the values. Enter your array elements: Enter element 1: 56 Enter element 2: 96 Enter element 3: 12 Enter element 4: 54 Enter element 5: 12 Enter element 6: 67 Enter element 7: 63 Enter element 8: 22 Enter element 9: 22 Enter element 10: 67 Enter a number to count the number of times it occurs in the array: 67 The number of times 67 occurs in the array is: 2

MUST BE IN WRITTEN IN C NEED ORIGINAL ANSWER! THANK YOU :)

Answer 1

#include <stdio.h>

int main() {
    int i, arr[10], num, count = 0;
    printf("Enter your array elements:\n");
    for (i = 0; i < 10; ++i) {
        printf("Enter element %d: ", i + 1);
        scanf("%d", &(arr[i]));
    }
    printf("Enter a number to count the number of times it occurs in the array: ");
    scanf("%d", &num);
    for (i = 0; i < 10; ++i) {
        if (arr[i] == num)
            ++count;
    }
    printf("The number of times %d occurs in the array is: %d\n", num, count);
    return 0;
}