Question

C++ Question.

Introduce a function that checks if a year is not a leap year.

Answer 1

#include <iostream>
using namespace std;
bool isLeap(int year) {
       bool leap = false;
       // if any year is divisable by 4 than there are many chances for leap year
       // except few
       if (year % 4 == 0) {
           // if it is divisable by 100 than it shoud also divisable by 400 like 2000 etc
           if (year % 100 == 0) {
               // year is divisible by 400, so the year is a leap year
               if (year % 400 == 0)
                   leap = true;
               else
                   leap = false;
           } else
               leap = true;
       } else
           leap = false;
       return leap;
   }
int main()
{
int year;   
cout<<"Enter year: ";
cin>>year;
if(isLeap(year))
cout<<year<<" is leap year";
else
cout<<year<<" is not leap year";

return 0;
}

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