Calculate the weight of 100 ppm solution required to create 15 g of each of the following: 1 ppm, 5 ppm, 10 ppm, 20 ppm, 30 ppm and 40 ppm Mg ion
Here concenrtaion is given in ppm
C1V1= C2V2
For 1 ppm
100 ppm * v2 = 1ppm *15 g
V2= 0.15 g
For 5 ppm
100 ppm * v2 = 5 ppm *15 g
V2= 0.75 g
For 10 ppm
100 ppm * v2 = 10 ppm *15 g
V2= 1.50 g
For 20 ppm
100 ppm * v2 = 20 ppm *15 g
V2= 3.00 g
For 30 ppm
100 ppm * v2 = 30 ppm *15 g
V2= 4.50 g
For 60 ppm
100 ppm * v2 = 60 ppm *15 g
V2= 6.00 g
Calculate the weight of 100 ppm solution required to create 15 g of each of the...
Solution Prep (a) The weight of MgCl2 required to create 1 kg of 1000 ppm Mg ion; (b)The weight of the 1000 ppm stock solution required to create a 15.0000 g of a 100 ppm sub-stock solution. (c) The weight of the 100 ppm solution required to create 15 g of each of the following: 1 ppm, 5 ppm, 10 ppm, 20 ppm, 30 ppm and 40 ppm Mg ion
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