Question

You are asked to design your own parallel plate capacitor that is capable of holding a...

You are asked to design your own parallel plate capacitor that is capable of holding a charge of 6.30 × 10−12 C when placed across a potential difference of 16.0 V. If the area of the plates is equal to 150 cm2 what must the plate separation be? What is the value of the capacitance of this capacitor?

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
You are asked to design your own parallel plate capacitor that is capable of holding a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...

    A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the initial capacitance of the air-filled capacitor. Determine the charge on the...

  • A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of...

    A parallel-plate capacitor has a plate area of A = 250 cm2 and a separation of d = 2.00 mm. The capacitor is charged to a potential difference of V0 = 150 V by a battery. A dielectric sheet (κ = 3.50) of the same area but thickness ℓ = 1.00 mm is placed between the plates without disconnecting the battery. (See figure 24-18 on page 642). Determine the electric field in the dielectric. Determine the free charge on the...

  • A parallel-plate capacitor with plate area 4.60 cm2 and air-gap separation 0.78 mm is connected to...

    A parallel-plate capacitor with plate area 4.60 cm2 and air-gap separation 0.78 mm is connected to a 12.00 V battery, and fully charged. The battery is then disconnected. (a) What is the charge on the capacitor? (b) The plates are now pulled to a separation of 0.98 mm. What is the charge on the capacitor now? (c) What is the potential difference across the plates now? (d) How much work was required to pull the plates to their new separation?...

  • A parallel plate capacitor is constructed with plate area of 0.80 m2 and a plate separation...

    A parallel plate capacitor is constructed with plate area of 0.80 m2 and a plate separation of 0.10 mm. When it is charged to a potential difference of 12 V, the charge stored on it is = micro C.   A parallel plate capacitor is constructed with plate area of 0.40 m2 and a plate separation of 0.10 mm. When it is charged to a potential difference of 12 V, the charge stored on it is= micro C.   A parallel-plate capacitor...

  • A parallel plate capacitor is constructed with plate area of 0.40 m2 and a plate separation...

    A parallel plate capacitor is constructed with plate area of 0.40 m2 and a plate separation of 0.10 mm. How much charge is stored on it when it is charged to a potential difference of 12 V? A parallel-plate capacitor is filled with air, and the plates are separated by 0.050 mm. If the capacitance is 17.3 pF, what is the plate area? A parallel plate capacitor is constructed with plate area of 0.0010 m2 and a plate separation of...

  • The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a...

    The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a separation of 8.80 mm are charged to a 130-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor. (a) What is the charge on the capacitor before and after the dielectric is inserted? Qi = ___C Qf = ____C (b) What is the capacitance of the capacitor after...

  • A parallel-plate capacitor has plates of area 0.13 m2 and a separation of 1.9 cm. A battery...

    A parallel-plate capacitor has plates of area 0.13 m2 and a separation of 1.9 cm. A battery charges the plates to a potential difference of 150 V and is then disconnected. A dielectric slab of thickness 9.3 mm and dielectric constant 4.0 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the...

  • 85. A parallel-plate capacitor with plate area 3.0 cm2 and air- gap separation 0.50 mm is...

    85. A parallel-plate capacitor with plate area 3.0 cm2 and air- gap separation 0.50 mm is connected to a 12-V battery, and fully charged. The battery is then disconnected. (a) What is the charge on the capacitor? (b) The plates are now pulled to a separation of 0.75 mm. What is the charge on the capacitor now? (c) What is the potential difference between the plates now? (d) How much work was required to pull the plates to their new...

  • Problem3 A parallel-plate capacitor with plate area 8.30 cm2 and air-gap separation 0.57 mm is connected...

    Problem3 A parallel-plate capacitor with plate area 8.30 cm2 and air-gap separation 0.57 mm is connected to a 12.00 V battery, and fully charged. The battery is then disconnected. a) What is the charge on the capacitor? Submit AnswerTries 0/6 atery and fully charged. The (b) The plates are now pulled to a separation of 0.81 mm. What is the charge on the capacitor now? Subnmit AnswerTries 0/6 (c) What is the potential difference across the plates now? Submit Answer...

  • The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates.

    The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates. While the battery remains connected, a dielectric slab of thickness b and dielectric constant κ is placed between the plates as shown. Assume A = 130 cm2, d = 1.94 cm, V0 = 72.6 V, b = 0.735 cm, and κ = 3.15. Calculate (a) the capacitance,(b) the charge on the capacitor plates,(c) the electric field in the gap, and(d)...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT