Question

Procedure I - Part D - Baby bugs when parents are Bb and Bb

Data Table - Enter your Baby Bug Counts from each data run

Data Run	BB Baby Bug Count	Bb Baby Bug Count	bb Baby Bug Count
1	3	3	4
2	3	6	1
3	0	9	1
4	1	8	1
5	4	5	1
6	1	6	3
7	4	3	3
8	2	4	4
9	2	6	2
10	3	4	3

Data Averages Table - Enter your average Baby Bug Counts

Tip: BB Baby Bug Count Average = Sum of BB Baby Bug Counts / Number of Data Runs

BB Baby Bug Count Average	Bb Baby Bug Count Average	bb Baby Bug Count Average
2.3	5.4	2.3

Percentage Tables - Enter the Baby Bug percentages

Tip: Baby Bug Percent = 100% ´ (Baby Bug Count Average) / (Total Number of Baby Bugs)

BB Baby Bug Percentage	Bb Baby Bug Percentage	bb Baby Bug Percentage
23%	54%	23%

Tip: Blue Rimmed Baby Bug Percentage = BB Baby Bug Percent + Bb Baby Bug Percent

Blue Rimmed Baby Bug Percentage	Yellow Rimmed Baby Bug Percentage
77%	23%

Observations and Questions

[13] Complete the Punnett square below when the parents are Bb and Bb.

Punnett Square	Male
Female	Alleles/Genes	B	B
	B	BB	Bb
	b	Bb	bb

[14] Using your Punnett Square, calculate the expected percentage of Blue Rimmed Baby Bugs and Yellow Rimmed Baby Bugs. Show your work. How do your percentage table results compare with the Punnett Square calculations? (higher, lower, similar) Explain your answer.

The percentage of the blue baby bugs=3/4X100=75%. The percentage of the yellow baby =1/4X100=25%. The percentage of the blue baby bug is 77% and the yellow baby bug is 23%.

[15] For Bb vs Bb parents, discuss how the genotype counts confirm the counts for the phenotypes in the display. Be specific. Use counts from one of your Bb vs Bb data runs as part of your discussion.

The genotypic count that was observed are: BB genotype23%, Bb genotype 54, bb genotype 23%.

Procedure II - Part A - Bug Population changes when there is a breeding preference for blue rimmed bugs

Data Table - Enter your Final Bug Counts

BB Bug Count	Bb Bug Count	bb Bug Count
18	2	0

                       

Percentage Tables - Enter the Final Bug percentages

Tip: Bug Type Percentage = 100% ´ (Bug Type Count) / (Total Number of Bugs)

BB Bug Percentage	Bb Bug Percentage	bb Bug Percentage
90%	10%	0%

Tip: Blue Rimmed Baby Bug Percentage = BB Bug Percent + Bb Bug Percent

Blue Rimmed Bug Percentage	Yellow Rimmed Bug Percentage
90%	0%

Observations and Questions

[16] Describe the bug population change results during this data run in terms of genotypes and phenotypes. There is a 90% chance there will BB, 10%Bb, and 0% bb with 90% of blue blug and 10% of yellow bugs. With that being said the equilibrium is affected by sexual selection of the blue bug.

[17] Do your results suggest anything about what the composition of this population might be at some distant point in the future? Defend your answer.

The blue bugs will be more predominant. There is a chance that the yellow bug will disappear. The blue bugs have higher sexual preferences. This will cause a higher proportion of BB.

[18] Based on the initial starting population, use the Hardy-Weinberg equation to predict the future bug population phenotype composition. Hint: Under the Background tab, go to the Summary of Formulas Needed for Calculations section, see the example titled Using the Hardy-Weinberg Equation, then do Step 1 and Step 2 using the initial starting population for this data run.

[19] Is this population consistent with the expectations of the Hardy-Weinberg model, that is, is this population stable? Hint: Under the Background tab, go to the Summary of Formulas Needed for Calculations section, see the example titled Using the Hardy-Weinberg Equation, then do Step 3 and Step 4 for this data run.

Answer 1