Describe how to make a 10 mL of 10% BSA solution (w/v) in water (show all formulas and calculations used to obtain a solution)?
1% solution means 1 gram of solute in 100 mL of solution.
So, 10% BSA will require 10 gram BSA in 100 mL of solution. But we need only 10 mL of solution. So, it will have 10/100 × 10 = 1 gram BSA.
So, dissolve 1 gram BSA in 2 mL of water and make final volume to 10 mL.
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Describe how to make a 10 mL of 10% BSA solution (w/v) in water (show all...
If you are making a 1:10 dilution of a 10mg/ml BSA solution using 90ul of water as diluent, how much 10mg/ml of BSA would you add? What would be your final concentration of BSA? If you assayed both these solutions using the Bradford assay which one would have a higher O.D.?
Rx: Zephiran Chloride Solution (17% w/v) q.s. Purified Water, to make 480 mL Sig: one tbsp. diluted to 1 gallon with water to make a 1:10,000 dilution. How many milliliters of zephiran chloride solution should be used in preparing the prescription?
Describe how to dilute a 20% stock solution to make 50.00 mL of a 2% solution using a 10 mL graduated cylinder and a 50.00 mL volumetric flask. Show calculations. Perform similar calculations for 5%, 10%, and 15% solutions. Show work.
Describe how much of each of the following stock components you would use to make 250mL of a solution with all of the components below (final concentration of each component is shown) (Show work) a) 1% (w/v) Stock: Dry powder (FW=58.0) b) 2 micrograms/microliter BSA Stock: 100mg/mL
Describe in complete sentences how to make 350 ml of a 18% m/v solution of mannitol (C6H14O6) using water as a solvent
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7) If you are making a 1:10 dilution of a 10mg/ml BSA solution using 90ul of water as diluent, how much 10mg/ml of BSA would you add? 8) What would be your final concentration of BSA? 9) If you assayed both these solutions using the Bradford assay which one would have a higher O.D.? 10) What device would you use to measure O.D.? 11) In your assay you would need a blank. What would you use as a blank? Water,...
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You collected 900 μL of 2 mg/mL BSA in water after a diafiltration step. Now you need to use this solution to make 200 μL of protein B at 1.25 mg/mL in 1X buffer. Using the 2 mg/mL BSA stock and the 10X buffer, make the desired solution. Here is how far I've gotten: C2= 1.25 V2= 200 C1= 2 V1= ? V1=(V2)(C2)/(C1) = 125 PLEASE HELP. I see many of these on Chegg already but I had a difficult...