Question

For the circuit in Figure 1, assme that the voltage drop across the infrared emitter is 1.3 V. Determine the value of RE that will set the current through the emitter to a value within the range of 50 mA to 80 mA. For the circuit in Figure 1, assume Rx 10 kQ and Vs 5 V. Using the equation given in the introduction section, determine the value of R needed to implement the Schmitt Trigger with a spread or hysteresis value between 0.5 V to 1 V. Use only standard resistor values in your lab kit. VREF must equal 2.5 V. In Lab 7, a buffer op-amp was used to provide this voltage. To reduce the component count, it is recommended that you use the same op-amp to provide VREF to both Modules 2 and 3. Use the same values of RouT, R1 and R2 that you used in Labs 6 and 7 0.01 uF 33 k 5 V 5.V Voo 5 V Voo Module 3 TIA MC Photo- diode IR Emitter Ri 5 v LED 5 V VRES VRE R2 Figure 1

R1= 12 K ohm

R2= 12 K ohm

rout= 1.2 K ohm

Answer 1

RE max TE 80 mA 5V I5-13 R513 80x1o 46.25 RE6.25 Fon 8chmitt tniggen, UTP Rx Rx+ RF o5Q.5 4 (-5 -2.5) Rx Rx+ RF Rx+RF Rx+RF R5 5x 133 K RF 33 Kn