The figure shows a person whose weight is W 700 N doing push-ups. Find the normal force exerted by the floor on (a)...

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Answer 1

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Answer #1

Let the force exerted on each hand be x and on each foot be y.

Balancing the net force along the vertical direction:

2*x + 2*y = 700 [Multiplication by two as there are two hands and feet]

x + y = 350

The torque about the center of gravity of the man should be balanced:

2x*0.410 = 2*y*0.840

That is, x = (0.840/0.410) * y = 2.049y

Substituting the value of x in terms of y in the above equation, we get: 2.049y + y = 350

(b) => y = 114.8 N

(a) Hence x = 350 – 114.8 = 235.2 N

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Answer 2

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